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0.2x^2=500
We move all terms to the left:
0.2x^2-(500)=0
a = 0.2; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·0.2·(-500)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*0.2}=\frac{-20}{0.4} =-50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*0.2}=\frac{20}{0.4} =50 $
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